3-4v^2=-21

Solution for 3-4v^2=-21 equation:

3-4v^2=-21

We move all terms to the left:

3-4v^2-(-21)=0

We add all the numbers together, and all the variables

-4v^2+24=0

a = -4; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-4)·24
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*-4}=\frac{0-8\sqrt{6}}{-8}
=-\frac{8\sqrt{6}}{-8}
=-\frac{\sqrt{6}}{-1}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*-4}=\frac{0+8\sqrt{6}}{-8}
=\frac{8\sqrt{6}}{-8}
=\frac{\sqrt{6}}{-1}
$